What is the power gain in dB when a transmitter's power increases from 5 watts to 50 watts?

Prepare for the Amateur Radio Operator Certificate Exam. Use flashcards and multiple choice questions, each featuring hints and explanations. Ace your exam with confidence!

To determine the power gain in decibels (dB) when a transmitter's power increases from 5 watts to 50 watts, you can use the formula for power gain in dB, which is:

[ \text{Gain (dB)} = 10 \times \log_{10}\left(\frac{P2}{P1}\right) ]

In this case, (P1) is 5 watts and (P2) is 50 watts. Plugging the values into the formula gives:

[ \text{Gain (dB)} = 10 \times \log_{10}\left(\frac{50}{5}\right) ]

[ = 10 \times \log_{10}(10) ]

[ = 10 \times 1 ]

[ = 10 , \text{dB} ]

This calculation shows that the power gain achieved when the transmitter's power increases from 5 watts to 50 watts is 10 dB. The logarithmic scale used for measuring gain allows for a simpler understanding of changes in power levels, as each 10 dB increase represents a tenfold increase in power level. Thus, a gain of 10 d

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