If two equal-value inductors are connected in parallel, what is the total inductance?

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When two equal-value inductors are connected in parallel, the total inductance can be determined using the formula for inductors in parallel, which is similar to the formula for resistors in parallel. For inductors, the total inductance (L_{total}) is calculated as:

[

\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2}

]

In the case of two equal-value inductors, let’s denote their common inductance as (L). The equation simplifies to:

[

\frac{1}{L_{total}} = \frac{1}{L} + \frac{1}{L} = \frac{2}{L}

]

By inverting both sides, we find:

[

L_{total} = \frac{L}{2}

]

Thus, the total inductance is indeed half the value of either inductor. This indicates that the correct answer is the total inductance is half the value of either inductor, not the same as the value. It's important to note that when inductors are combined in parallel, they do not produce a total inductance that remains equal to the individual induct

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